| Line 33: | Line 33: | ||
---- | ---- | ||
| + | |||
| + | Question from Christine | ||
| + | |||
| + | For problems p.159: I am looking for some suggestion for starting #7. Factoring with the two variables to get the eigen values is not working out...? Thanks! | ||
| + | |||
[[2013_Fall_MA_527_Bell|Back to MA527, Fall 2013]] | [[2013_Fall_MA_527_Bell|Back to MA527, Fall 2013]] | ||
Revision as of 16:32, 22 September 2013
Homework 5 collaboration area
Question from Ryan Russon
For problems p.159: 4,7,11 are we supposed to accompany each solution with a sketch of the what is happening at the critical points or are we fine just stating what is happening at those points based on the eigenvalues of the linearized system? My confusion is stemming from the answer in the back of the book for #11 which says, "Use -cos(+- 1/2...)," you get the picture.
Answer from Steve Bell :
Those problems don't seem to ask for a sketch, so don't bother. (If you wanted to practice for the exam, testing yourself to see if you would know how to draw a sketch if you had to would be therapeutic.)
That cryptic remark about the trig identity can be used like so
$ -\cos(\frac{\pi}{2}+ x)=\sin x = x -\frac{1}{3!}x ^3 +\dots \approx x $
(when x is small) to realize that the linearized system at the critical point (pi/2,0) has a 1 times y1 in that spot. I think it's easier to use the Jacobian matrix to find the first order Taylor term the way I demonstrated in class to see this.
Response from Ryan Russon
Thanks Steve! Using the Jacobian is how I approached it and it is a lot more intuitive for me to approach it that way.
Question from Christine
For problems p.159: I am looking for some suggestion for starting #7. Factoring with the two variables to get the eigen values is not working out...? Thanks!
