Line 19: | Line 19: | ||
==Share your answers below== | ==Share your answers below== | ||
You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too! | You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too! | ||
+ | |||
+ | '''No need to write your name: we can find out who wrote what by checking the history of the page.''' | ||
---- | ---- | ||
===Answer 1=== | ===Answer 1=== | ||
− | |||
− | |||
<math> x[n] = u[n+2]-u[n-1]</math>. | <math> x[n] = u[n+2]-u[n-1]</math>. | ||
Line 34: | Line 34: | ||
===Answer 2=== | ===Answer 2=== | ||
− | + | ||
[[Image:green26_ece438_hmwrk3_rect.png|480x320px]] | [[Image:green26_ece438_hmwrk3_rect.png|480x320px]] |
Revision as of 15:30, 12 September 2013
Contents
Practice Problem on Discrete-time Fourier transform computation
Compute the discrete-time Fourier transform of the following signal:
$ x[n]= u[n+2]-u[n-1] $
See these Signal Definitions if you do not know what is the step function "u[n]".
(Write enough intermediate steps to fully justify your answer.)
You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!
No need to write your name: we can find out who wrote what by checking the history of the page.
Answer 1
$ x[n] = u[n+2]-u[n-1] $.
$ X_(\omega) = \sum_{n=-\infty}^{+\infty} x[n] e^{-j\omega n} $
$ = \sum_{n=-2}^{0} x[n] e^{-j\omega n} $
$ = 1+ e^{j\omega} + e^{2j\omega} $
Answer 2
$ X_{2\pi}(\omega) = \sum_{n=-\infty}^{+\infty} x[n] e^{-j\omega n} $
$ = \sum_{n=-2}^{0} x[n] e^{-j\omega n} $
$ = e^{2j\omega} + e^{j\omega} + 1 $
Answer 3
Write it here.