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===Answer 1=== | ===Answer 1=== | ||
| − | + | The mean of a random variable is defined as: | |
| + | |||
| + | <math> | ||
| + | \int \! x*f_X(x) \, \mathrm{d}x. | ||
| + | </math> | ||
| + | |||
| + | Since the probability density function is k on the interval a to b and zero everywhere else, we can simply write: | ||
| + | |||
| + | <math> | ||
| + | => \int_a^b \! x*k \, \mathrm{d}x. | ||
| + | </math> | ||
| + | |||
| + | Thus solving we get | ||
| + | |||
| + | <math> | ||
| + | = 1/2x^2k|_a^b | ||
| + | </math> | ||
| + | |||
| + | |||
| + | <math> | ||
| + | = \frac{k}{2}(b^2-a^2) | ||
| + | </math> | ||
| + | |||
===Answer 2=== | ===Answer 2=== | ||
Write it here | Write it here | ||
Revision as of 14:33, 22 March 2013
Contents
Practice Problem: normalizing the probability mass function of a continuous random variable
A random variable X has the following probability density function:
$ f_X (x) = \left\{ \begin{array}{ll} k, & \text{ if } a\leq x \leq b,\\ 0, & \text{ else}, \end{array} \right. $
where k is a constant. Compute the mean of X.
You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!
Answer 1
The mean of a random variable is defined as:
$ \int \! x*f_X(x) \, \mathrm{d}x. $
Since the probability density function is k on the interval a to b and zero everywhere else, we can simply write:
$ => \int_a^b \! x*k \, \mathrm{d}x. $
Thus solving we get
$ = 1/2x^2k|_a^b $
$ = \frac{k}{2}(b^2-a^2) $
Answer 2
Write it here
Answer 3
Write it here.
