(New page: ===SUBSPACE=== To be a subspace of vectors the following must be true: 1. One set must be a '''subset''' of another set 2. The set must be closed under '''scalar multiplication''' 3. T...) |
|||
Line 1: | Line 1: | ||
+ | |||
+ | == | ||
+ | == VECTOR SPACE == | ||
+ | == | ||
+ | |||
+ | |||
+ | |||
+ | |||
+ | |||
+ | |||
===SUBSPACE=== | ===SUBSPACE=== | ||
Line 97: | Line 107: | ||
'''Example''' | '''Example''' | ||
− | Let V be the set of points | + | Let V be the set of points in R^2 such that x=y |
Line 104: | Line 114: | ||
1. What it means for '''v''' and '''w''' to be in V : | 1. What it means for '''v''' and '''w''' to be in V : | ||
− | '''v''' = (v1, v2) and | + | '''v''' = (v1, v2) and v1 = v2 |
− | '''w''' = (w1, w2) and | + | '''w''' = (w1, w2) and w1 = w2 |
− | 2. '''z''' | + | 2. '''z''' = '''v''' + '''w''' = (v1+w1, v2+w2) = (v1+w1, v1+w1) |
− | |||
− | 3. What it means for '''z''' to be in V: | + | 3. What it means for '''z''' to be in V: v1+w1 = v2+w2 |
Revision as of 10:14, 3 December 2012
==
Contents
VECTOR SPACE
==
SUBSPACE
To be a subspace of vectors the following must be true:
1. One set must be a subset of another set
2. The set must be closed under scalar multiplication
3. The set must be closed under vector addition
Proving one set is a subset of another set
Given sets A and B we say that is is a subset of B if every element of A is also an element of B, that is,
x∈A implies x∈B
Basic Outline of the Proof that A is a subset of B:
· Suppose x ∈ A
1. Say what it means for x to be in A
2. Mathematical details
3. Conclude that x satisfies what it means to be in B
· Conclude x∈B
Example
Let A be the set of scalars divisible by 6 and let B be the even numbers. Prove that A is a subset of B.
· Suppose x ∈ A:
1. What it means for x to be in A: x = 6k for any scalar k
2. x = 2 × (3k)
3k = C
3. What it means for x to be in B: x = 2C
· Conclude x∈B
Closed Under Scalar Multiplication
A set of vectors is closed under scalar multiplication if for every v∈V and every c∈\mathbb{R} we have cv∈V
Basic Outline of the Proof V is Closed Under Scalar Multiplication:
· Suppose v∈V and c∈\mathbb{R}
1. Say what it means for v to be in V
2. Mathematical details
3. Conclude that cv satisfies what it means to be in V
· Conclude cv∈V
Closed Under Vector Addition
A set of vectors is closed under vector addition if for every v and w ∈ V we have v + w ∈ V
Basic Outline of the Proof V is Closed Under Vector Addition:
· Suppose v and w ∈ V
1. Say what it means for v and w to be in V
2. Mathematical details
3. Conclude that v+ w satisfies what it means to be in V
· Conclude v + w ∈ V
Example
Let V be the set of points in R^2 such that x=y
· Suppose v and w ∈ V
1. What it means for v and w to be in V :
v = (v1, v2) and v1 = v2
w = (w1, w2) and w1 = w2
2. z = v + w = (v1+w1, v2+w2) = (v1+w1, v1+w1)
3. What it means for z to be in V: v1+w1 = v2+w2
· Conclude z = v + w ∈ V
Explanation of how to determine a subspace. Information referenced from Wabash College MA 223, Spring 2011