(New page: Defining equation for the DFT and assume that N is even, so we have<br> <math>X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}}<\math><br><br>)
 
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Defining equation for the DFT and assume that N is even, so we have<br>
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Defining equation for the DFT and assume that N is even, so we have<br>  
  
&lt;math&gt;X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}}&lt;\math&gt;<br><br>
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<math>X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}}</math><br><br>

Revision as of 17:02, 7 November 2012

Defining equation for the DFT and assume that N is even, so we have

$ X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}} $

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