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Revision as of 05:26, 2 November 2011
If you enjoy using this collective table of formulas, please consider donating to Project Rhea or becoming a sponsor. |
Complex Number Identities and Formulas (info) | |
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Basic Definitions | |
imaginary number | $ i=\sqrt{-1} \ $ |
electrical engineers' imaginary number | $ j=\sqrt{-1}\ $ |
(info) conjugate of a complex number | if $ z=a+ib $, for $ a,b\in {\mathbb R} $, then $ \bar{z}=a-ib $ |
(info) magnitude of a complex number | $ \| z \| = z \bar{z} $ |
(info) magnitude of a complex number | $ \| z \| = \sqrt{\left(Re(z)\right)^2+\left(Im(z)\right)^2} $ |
(info) magnitude of a complex number | $ \| a+ib \| = \sqrt{a^2+b^2} $, for $ a,b\in {\mathbb R} $ |
(info) magnitude of a complex number | $ \| r e^{i \theta} \| = r $, for $ r,\theta\in {\mathbb R} $ |
Complex Number Operations | |
addition | $ (a+ib)+(c+id)=(a+c) + i (b+d) \ $ |
multiplication | $ (a+ib) (c+id)=(ac-bd) + i (ad+bc) \ $ |
multiplication in polar form | $ \left( r_1 (\cos \theta_1 + i \sin \theta_1) \right) \left( r_2 (\cos \theta_2 + i \sin \theta_2) \right)= r_1 r_2 \left( \cos (\theta_1+\theta_2)+i \sin (\theta_1-\theta_2) \right)\ $ |
division | $ \frac{a+ib} {c+id}=\frac{ac+bd} {c^2+d^2}+ i \frac{bc-ad} {c^2+d^2} \ $ |
division in polar form | $ \frac{ r_1 (\cos \theta_1 + i \sin \theta_1)}{ r_2 (\cos \theta_2 + i \sin \theta_2) }= \frac{r_1}{ r_2} \left( \cos (\theta_1-\theta_2)+i \sin (\theta_1+\theta_2) \right)\ $ |
exponentiation | $ i^n =\left\{ \begin{array}{ll}1,& \text{when }n\equiv 0\mod 4 \\ i,& \text{when }n\equiv 1\mod 4 \\-1,& \text{when }n\equiv 2\mod 4 \\-i,& \text{when }n\equiv 3\mod 4 \end{array} \right. \ $ |
Euler's Formula and Related Equalities (info) | |
(info) Euler's formula | $ e^{iw_0t}=\cos w_0t+i\sin w_0t \ $ |
A really cute formula | $ e^{i\pi}=-1 \ $ |
Cosine function in terms of complex exponentials | $ \cos\theta=\frac{e^{i\theta}+e^{-i\theta}}{2} $ |
Sine function in terms of complex exponentials | $ \sin\theta=\frac{e^{i\theta}-e^{-i\theta}}{2i} $ |
Other Formulas | |
De Moivre's theorem | $ \left(\cos x+i\sin x\right)^n=\cos\left(nx\right)+i\sin\left(nx\right).\, $ |
Root of a complex number | $ \left( r (\cos x+i\sin x) \right)^{\frac{1}{n}}=r^{\frac{1}{n}} \cos\left(\frac{x+2 k \pi}{n}\right) +i\sin\left(\frac{x+2 k \pi}{n} \right), k=0,1,\ldots, n-1.\, $ |