(New page: Category:ECE301 Category:ECE438 Category:ECE438Fall2011Boutin Category:problem solving = Properties of the Z-transform = Prove the following scaling property of the z-trans...)
 
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===Answer 1===
 
===Answer 1===
Write it here.
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I think there is a mistake, it should be <math>z_0^n</math> instead of <math>z_0^2</math>.
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proof:
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<math>x'[n]=z_0^n x[n]</math>
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<math>Z[x'[n]]=\sum_{n=-\infty}^{\infty}x'[n]z^{-n}=\sum_{n=-\infty}^{\infty}z_0^n x[n]z^{-n}=\sum_{n=-\infty}^{\infty}x[n](\frac{z}{z_0})^{-n}</math>
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<math>let k=\frac{z}{z_0}</math>
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<math>Z[z_0^n x[n]]=\sum_{n=-\infty}^{\infty}x[n]k^{-n}=X(k)=X(\frac{z}{z_0})</math>
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=== Answer 2===
 
=== Answer 2===
 
Write it here.
 
Write it here.

Revision as of 09:09, 10 September 2011

Properties of the Z-transform

Prove the following scaling property of the z-transform:

$ z_0^2 x[n] \rightarrow X \left( \frac{z}{z_0}\right) $


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You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!


Answer 1

I think there is a mistake, it should be $ z_0^n $ instead of $ z_0^2 $.

proof:

$ x'[n]=z_0^n x[n] $

$ Z[x'[n]]=\sum_{n=-\infty}^{\infty}x'[n]z^{-n}=\sum_{n=-\infty}^{\infty}z_0^n x[n]z^{-n}=\sum_{n=-\infty}^{\infty}x[n](\frac{z}{z_0})^{-n} $

$ let k=\frac{z}{z_0} $

$ Z[z_0^n x[n]]=\sum_{n=-\infty}^{\infty}x[n]k^{-n}=X(k)=X(\frac{z}{z_0}) $

Answer 2

Write it here.


Back to ECE438 Fall 2011 Prof. Boutin

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang