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:<span style="color:green">Instructor's comments: Did you actually try it in MATLAB? Did it work? -pm </span> | :<span style="color:green">Instructor's comments: Did you actually try it in MATLAB? Did it work? -pm </span> | ||
===Answer 2=== | ===Answer 2=== | ||
| − | + | I chose the sample rate to be 1/1000. | |
| + | |||
| + | n = 1:10000; | ||
| + | |||
| + | x = cos(2*pi*400*n/1000); | ||
| + | |||
| + | x = x'; | ||
| + | |||
| + | sound(x) | ||
| + | |||
| + | |||
| + | |||
===Answer 3=== | ===Answer 3=== | ||
write it here. | write it here. | ||
---- | ---- | ||
[[2011_Fall_ECE_438_Boutin|Back to ECE438 Fall 2011 Prof. Boutin]] | [[2011_Fall_ECE_438_Boutin|Back to ECE438 Fall 2011 Prof. Boutin]] | ||
Revision as of 15:23, 6 September 2011
Contents
Sampling of an A 440
Explain how one can use MATLAB to play an A 440. Discuss your choice of sampling rate. (Feel free to post a sound file of your output.)
You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!
Answer 1
The signal we want is $ x(t) = cos(440 * 2\pi) $.
We can first create a vector of sample times. In this case, we'll let the sample frequency be 1320 Hz over a sample interval of [0,1]
t = 0:(1/1320):1;
Next, we can generate the sound samples vector from the sample times vector.
y = cos(440*2*pi*t);
Finally, we play the signal by using the "sound" command, which needs the user to specify the sound vector and the sample rate of that vector. Our sample was 1320.
sound(y, 1320);
The sample frequency was chosen so that it was more than twice the note frequency, so that the signal could be completely recovered from this sample.
- Instructor's comments: Did you actually try it in MATLAB? Did it work? -pm
Answer 2
I chose the sample rate to be 1/1000.
n = 1:10000;
x = cos(2*pi*400*n/1000);
x = x';
sound(x)
Answer 3
write it here.
