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− | [[Category:ECE301 S11 Exam 3 more practice]][[Category: | + | [[Category:ECE301 S11 Exam 3 more practice]] |
+ | [[Category:ECE301Spring2011Boutin]] | ||
+ | [[Category:Problem_solving]] | ||
− | = | + | = Problem = |
+ | Compute the convolution | ||
+ | <math>z(t)=x(t)*y(t) \ </math> | ||
+ | between | ||
− | + | <math> x(t) = e^{jwt}u(t+2) \ </math> | |
− | + | ||
+ | and | ||
+ | <math>y(t) = e^{jwt}u(t-2) \ </math>. | ||
+ | = My Solution= | ||
+ | <math> | ||
+ | \begin{align} | ||
+ | z(t) &= e^{jwt}u(t+2) * e^{jwt}u(t-2) \\ | ||
+ | &= \int_{-\infty}^{\infty} e^{jw\tau}u(\tau+2) e^{jw(t- \tau)}u(t - \tau -2)\mathrm{d}\tau \\ | ||
+ | &= \int_{-2}^{t-2} e^{jw\tau} e^{jw(t- \tau)}\mathrm{d}\tau \\ | ||
+ | &= e^{jwt} \int_{-2}^{t-2} 1 \mathrm{d}\tau \\ | ||
+ | &= \begin{cases} | ||
+ | t e^{jwt} &, \text{when }t > 2 \\ | ||
+ | 0 &, \text{else}\end{cases} | ||
+ | \end{align} | ||
+ | </math> | ||
+ | ==Comments== | ||
+ | Write them here. | ||
+ | ---- | ||
[[ ECE301 S11 Exam 3 more practice|Back to ECE301 S11 Exam 3 more practice]] | [[ ECE301 S11 Exam 3 more practice|Back to ECE301 S11 Exam 3 more practice]] |
Latest revision as of 05:04, 6 May 2011
Problem
Compute the convolution
$ z(t)=x(t)*y(t) \ $
between
$ x(t) = e^{jwt}u(t+2) \ $
and
$ y(t) = e^{jwt}u(t-2) \ $.
My Solution
$ \begin{align} z(t) &= e^{jwt}u(t+2) * e^{jwt}u(t-2) \\ &= \int_{-\infty}^{\infty} e^{jw\tau}u(\tau+2) e^{jw(t- \tau)}u(t - \tau -2)\mathrm{d}\tau \\ &= \int_{-2}^{t-2} e^{jw\tau} e^{jw(t- \tau)}\mathrm{d}\tau \\ &= e^{jwt} \int_{-2}^{t-2} 1 \mathrm{d}\tau \\ &= \begin{cases} t e^{jwt} &, \text{when }t > 2 \\ 0 &, \text{else}\end{cases} \end{align} $
Comments
Write them here.