(New page: I'm having a hard time proving 1a is stable or unstable. If (|x[n]|<m) then is it also true that (|x[n-1]|<m)? I'm assuming the product of two bounded signals also give a bounded sys...)
 
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I'm having a hard time proving 1a is stable or unstable. If (|x[n]|&lt;m) then is it also true that (|x[n-1]|&lt;m)? I'm assuming the product of two bounded signals also give a bounded system.
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I'm having a hard time proving 1a is stable or unstable. If (|x[n]|&lt;m) then is it also true that (|x[n-1]|&lt;m)? I'm assuming the product of two bounded signals also gives a bounded signal.

Revision as of 11:28, 1 February 2011

I'm having a hard time proving 1a is stable or unstable. If (|x[n]|<m) then is it also true that (|x[n-1]|<m)? I'm assuming the product of two bounded signals also gives a bounded signal.

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Correspondence Chess Grandmaster and Purdue Alumni

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