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– <math>\inf S=0</math> . However, the minimum does not exist.
 
– <math>\inf S=0</math> . However, the minimum does not exist.
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='''Well-known sets'''=
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• <math>\mathbb{N}</math> : the set of natural numbers. It is countably infinite.
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– <math>\mathbb{N}_{0}=\left\{ 0,1,\cdots\right\}</math> 
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– <math>\mathbb{N}^{*}=\mathbb{N}_{1}=\left\{ 1,2,\cdots\right\}</math> 
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• <math>\mathbb{Z}_{n}</math> : the set of modulo <math>n</math>

Revision as of 11:23, 16 November 2010

1.1 Basic Mathematics

1.1.1 Mathematical notation

 : approximately equal

~ : CST ·

Supremum and infimum vs. maximum and minimum

The concept of supremum, or least upper bound, is as follows: Let $ S={a[n]} $, the sequence with terms $ a[0],a[1],\cdots $ over all the nonnegative integers. $ S $ has a supremum, called $ \sup S $ , if for every $ n , a[n]\leq\sup S $ (i.e. no a[n] exceeds $ \sup S $ ), and furthermore, $ \sup S $ is the least value with this property; that is, if $ a[n]\leq b $ for all $ n $, then $ \sup S\leq b $ for all such $ b $ . This is why the supremum is also called the least upper bound, for a bound is a number which a function, sequence, or set, never exceeds. Similarly, one can define the infimum $ \inf S $ , or greatest lower bound.


• Consider the set $ \left\{ x:\;0<x<1\right\} $ . There is no maximum or minimum, however $ 0 $ is the infimum and $ 1 $ is the supremum.

• Consider the set $ S={a[n]},\; a[n]=1/n $ where $ n $ is a positive integer.

$ \sup S=1 $ , since $ 1/n>1/(n+1) $ for all such $ n $ , and so the largest term is the first. The maximum is also $ 1 $.

$ \inf S=0 $ . However, the minimum does not exist.

Well-known sets

$ \mathbb{N} $ : the set of natural numbers. It is countably infinite.

$ \mathbb{N}_{0}=\left\{ 0,1,\cdots\right\} $

$ \mathbb{N}^{*}=\mathbb{N}_{1}=\left\{ 1,2,\cdots\right\} $

$ \mathbb{Z}_{n} $ : the set of modulo $ n $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood