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<math>x[n] = 4^n u[n+3] - 4^n u[n-4]</math>
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<math>x[n] = \sum_{n=-\infty}^{\infty} 4^n u[n+3] z^{-n} - \sum_{n=-\infty}^{\infty} 4^n u[n-4] z^{-n}</math>
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<math>x[n] = \sum_{n=3}^{\infty} 4^n z^{-n} - \sum_{n=-\infty}^{4} 4^n z^{-n}</math>
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<math>x[n] = \sum_{n=0}^{\infty} (\frac{4}{z})^n - 85 - \sum_{n=4}^{\infty} 4^n z^{-n}</math>
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this is the mistake I made on my exam - could you please clarify my work, professor?
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Revision as of 02:56, 19 October 2010

Practice Question 2, ECE438 Fall 2010, Prof. Boutin

On Computing the z-tramsfprm of a discrete-time signal.


Compute the z-transform of the discrete-time signal

$ x[n]= 4^n \left(u[n+3]-u[n-4] \right) $.

Note: there are two tricky parts in this problem. Do you know what they are?


Post Your answer/questions below.

$ x[n] = 4^n u[n+3] - 4^n u[n-4] $

$ x[n] = \sum_{n=-\infty}^{\infty} 4^n u[n+3] z^{-n} - \sum_{n=-\infty}^{\infty} 4^n u[n-4] z^{-n} $

$ x[n] = \sum_{n=3}^{\infty} 4^n z^{-n} - \sum_{n=-\infty}^{4} 4^n z^{-n} $

$ x[n] = \sum_{n=0}^{\infty} (\frac{4}{z})^n - 85 - \sum_{n=4}^{\infty} 4^n z^{-n} $

this is the mistake I made on my exam - could you please clarify my work, professor?


  • Answer/question
  • Answer/question
  • Answer/question

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