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There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways. | There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways. | ||
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| + | Grading Comment: | ||
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| + | I believe the answer is correct. I did the same thing too. So, if I'm a grader for this course, I'll give you full mark. :) | ||
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| + | --[[User:Mmohamad|hussaini]] 18:20, 5 October 2008 (UTC) | ||
Latest revision as of 13:20, 5 October 2008
By listing the possibilities, we get:
3 + 1 + 1 = 5
2 + 2 + 1 = 5
4 + 1 + 0 = 5
5 + 0 + 0 = 5
3 + 2 + 0 = 5
There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways.
Grading Comment:
I believe the answer is correct. I did the same thing too. So, if I'm a grader for this course, I'll give you full mark. :)
--hussaini 18:20, 5 October 2008 (UTC)
