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| <math> X(f)=\mathcal{X}(2\pi f)=\mathcal{F}(x(t))=\int_{-\infty}^{\infty} x(t) e^{-i2\pi ft} dt</math>  
 
| <math> X(f)=\mathcal{X}(2\pi f)=\mathcal{F}(x(t))=\int_{-\infty}^{\infty} x(t) e^{-i2\pi ft} dt</math>  
 
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Revision as of 19:46, 9 September 2010

CT Fourier Transform
$ X(f)=\mathcal{X}(2\pi f)=\mathcal{F}(x(t))=\int_{-\infty}^{\infty} x(t) e^{-i2\pi ft} dt $

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