Line 9: Line 9:
 
For problem 7 on the practice problem worksheet, would it be valid to just let be z equal to the curve R*exp(it) in the integrand and take the limit as R goes to infinity, of the integral showing that the integrand approaches 0 and thus the integral goes to 0?--[[User:Apdelanc|Adrian Delancy]]
 
For problem 7 on the practice problem worksheet, would it be valid to just let be z equal to the curve R*exp(it) in the integrand and take the limit as R goes to infinity, of the integral showing that the integrand approaches 0 and thus the integral goes to 0?--[[User:Apdelanc|Adrian Delancy]]
  
Adrian, no that isn't enough because the ''length'' of the curve goes to infinity at the same time that the integrand goes to zero.  It is a more subtle problem and you need to use the estimate that I used in class today.  See my notes at
+
Adrian, no that isn't enough because the ''length'' of the curve goes to infinity at the same time that the integrand goes to zero.  It is a more subtle problem and you need to use the estimate that I used in class today.
 +
--[[User:Bell|Steve Bell]] See my notes at
  
[http://www.math.purdue.edu/~bell/MA425/Lectures/lec10-05.pdf lec10-05.pdf] --[[User:Bell|Steve Bell]]
+
[http://www.math.purdue.edu/~bell/MA425/Lectures/lec10-05.pdf lec10-05.pdf]

Revision as of 08:43, 5 October 2009


Discussion area to prepare for Exam 1

Practice Problems for Exam 1


Professor Bell, For problem 7 on the practice problem worksheet, would it be valid to just let be z equal to the curve R*exp(it) in the integrand and take the limit as R goes to infinity, of the integral showing that the integrand approaches 0 and thus the integral goes to 0?--Adrian Delancy

Adrian, no that isn't enough because the length of the curve goes to infinity at the same time that the integrand goes to zero. It is a more subtle problem and you need to use the estimate that I used in class today. --Steve Bell See my notes at

lec10-05.pdf

Alumni Liaison

Meet a recent graduate heading to Sweden for a Postdoctorate.

Christine Berkesch