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<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha)</math>
+
<math>\sum_{n = M}^N \alpha^n = \frac{\alpha^M - \alpha^{N-1}}{(1 - \alpha)}</math>
  
 
*What if <math>\alpha=1</math>????
 
*What if <math>\alpha=1</math>????

Revision as of 07:14, 29 September 2010

$ \sum_{n = M}^N \alpha^n = \frac{\alpha^M - \alpha^{N-1}}{(1 - \alpha)} $

  • What if $ \alpha=1 $????

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett