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<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha)</math>
 
<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha)</math>
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*What if <math>\alpha=1</math>????

Revision as of 05:45, 20 July 2009

$ \sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha) $

  • What if $ \alpha=1 $????

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang