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Don't know what that will do, but we'll see. [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] | Don't know what that will do, but we'll see. [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] | ||
| − | Nevermind, I figured it out. You just have to do a second comparison between the resultant denominator in the limit with a simpler version, and show how that the limit is less than one. | + | Nevermind, I figured it out. You just have to do a second comparison between the resultant denominator in the limit with a simpler version, and show how that the limit is less than one. If you have difficulty, just give me a shout |
[[User:Jhunsber|His Awesomeness, Josh Hunsberger]] | [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] | ||
Revision as of 19:03, 4 November 2008
Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me.
$ \frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}} $
Don't know what that will do, but we'll see. His Awesomeness, Josh Hunsberger
Nevermind, I figured it out. You just have to do a second comparison between the resultant denominator in the limit with a simpler version, and show how that the limit is less than one. If you have difficulty, just give me a shout
