Difference between revisions of "Page 569, Problem 15 MA181Fall2008bell" - Rhea

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-This one looks pretty easy, but I keep getting the wrong answer. Here's the problem.
-<math>\int_{0}^{2Pi}\sqrt{\frac{1-\cos{x}}{2}}dx</math>
-Obviously, <math>\frac{1-\cos{x}}{2} = \sin^2{\frac{x}{2}}</math>
-So, the integral should then look like:
-<math>\int_{0}^{2Pi}\sin{\frac{x}{2}}dx</math>
-Integrated, it comes out to:
-<math>[-2\cos{\frac{x}{2}}]_{0}^{2Pi}</math>

Latest revision as of 11:21, 19 October 2008