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* I didn't get the right answer according to the back of the book. I got:
 
  
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<math>x + 4 = Ax + A + Bx - 6B = (A + B)x + A - 6B</math>
 
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Meaning:
 
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<math>A + B = 1</math> 
 
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and
 
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<math>A - 6B = 4</math>
 
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So, <math>A = \frac{10}{7}</math>  and  <math>B = -\frac{3}{7}</math>
 
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The answer in the back of the book is
 
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<math>\frac{1}{7}\ln{|(x+6)^2(x-1)^5|}+C</math>
 

Latest revision as of 12:06, 13 October 2008

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