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<math> \Rightarrow ~y(t) \le B\int_{-\infty}^{\infty} e^t[u(t-2) - u(t-5)]\, dt </math>
 
<math> \Rightarrow ~y(t) \le B\int_{-\infty}^{\infty} e^t[u(t-2) - u(t-5)]\, dt </math>
 +
 +
<math> \Rightarrow ~y(t) \le B\int_{2}^{5} e^t\, dt </math>

Revision as of 11:59, 1 July 2008

I thought that the solution posted in the Bonus 3 for problem 4 is slightly wrong in explaining why System II is Stable.

Its given that $ x(t) \le B $

$ y(t) = x(t) * h(t) = \int_{-\infty}^{\infty} x(t)h(t)\, dt $

$ \Rightarrow ~y(t) \le \int_{-\infty}^{\infty} Bh(t)\, dt $

$ \Rightarrow ~y(t) \le B\int_{-\infty}^{\infty} e^t[u(t-2) - u(t-5)]\, dt $

$ \Rightarrow ~y(t) \le B\int_{2}^{5} e^t\, dt $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood