Line 1: Line 1:
If Independent then P(H)*P(T)=P(H∩T)
+
If Independent then P(H)*P(T)=P(H∩T)
  
Sample Case: One flip of coin
+
Sample Case: One flip of coin
  
P(H)=0.5
+
P(H)=0.5
 
  P(T)=0.5
 
  P(T)=0.5
 
  P(H∩T)=0 (You can't have both H and T in one flip)
 
  P(H∩T)=0 (You can't have both H and T in one flip)
  
(0.5)*(0.5)≠0
+
(0.5)*(0.5)≠0
 
  Not independent
 
  Not independent

Revision as of 19:07, 4 March 2009

If Independent then P(H)*P(T)=P(H∩T)
Sample Case: One flip of coin
P(H)=0.5
P(T)=0.5
P(H∩T)=0 (You can't have both H and T in one flip)
(0.5)*(0.5)≠0
Not independent

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood