Line 1: Line 1:
 
1 a)
 
1 a)
  
<math>x_(t) \,\!= \cos(\frac{\pi}{2})rect(\frac{t}{2})</math>
+
<math>x(t) \,\!= \cos(\frac{\pi}{2})rect(\frac{t}{2})</math>
  
 
Based on the Prof Alen's note page 179  
 
Based on the Prof Alen's note page 179  
  
<math>x_(f) \,\!= \frac{1}{2}( \delta (f - \frac{1}{4}) + \delta (f + \frac{1}{4}))sinc(t/2)</math>
+
<math>x(f) \,\!= \frac{1}{2}( \delta (f - \frac{1}{4}) + \delta (f + \frac{1}{4}))sinc(t/2)</math>
 
*<span style="color:red">Would you know how to compute this FT without a table if asked? </span> --[[User:Mboutin|Mboutin]] 10:45, 9 February 2009 (UTC)  
 
*<span style="color:red">Would you know how to compute this FT without a table if asked? </span> --[[User:Mboutin|Mboutin]] 10:45, 9 February 2009 (UTC)  
  
Line 17: Line 17:
  
 
First take the x(t) from part a and call it <math>x_1(t)</math>
 
First take the x(t) from part a and call it <math>x_1(t)</math>
<math>x_1(t) \,\!= \cos(\frac{\pi t}{2})rect(\frac{t}{2})</math>
+
<math>x1(t) \,\!= \cos(\frac{\pi t}{2})rect(\frac{t}{2})</math>
  
 
Now since this is a repeating function use the rep function to get
 
Now since this is a repeating function use the rep function to get
Line 23: Line 23:
  
 
We know that the CTFT of x1(t) is:<br/>
 
We know that the CTFT of x1(t) is:<br/>
<math>x_1(f) = sinc(2(f-\frac{1}{4} ) + sinc(2(f + \frac{1}{4})</math><br/>
+
<math>x1(f) = sinc(2(f-\frac{1}{4} ) + sinc(2(f + \frac{1}{4})</math><br/>
 
We also know from alabechs notes section 1.4.1 that
 
We also know from alabechs notes section 1.4.1 that
 
<math> rep_T(x_1(t)) \Rightarrow \frac{1}{T} comb_{1/T}(X_1(f))</math><br/>
 
<math> rep_T(x_1(t)) \Rightarrow \frac{1}{T} comb_{1/T}(X_1(f))</math><br/>

Revision as of 18:22, 10 February 2009

1 a)

$ x(t) \,\!= \cos(\frac{\pi}{2})rect(\frac{t}{2}) $

Based on the Prof Alen's note page 179

$ x(f) \,\!= \frac{1}{2}( \delta (f - \frac{1}{4}) + \delta (f + \frac{1}{4}))sinc(t/2) $

  • Would you know how to compute this FT without a table if asked? --Mboutin 10:45, 9 February 2009 (UTC)

An answer to this 1a) question is stated in the discussion [1]


b)

This is how I came to my conclusion, I think it makes morse sense then the previous mentioned answer.

First take the x(t) from part a and call it $ x_1(t) $ $ x1(t) \,\!= \cos(\frac{\pi t}{2})rect(\frac{t}{2}) $

Now since this is a repeating function use the rep function to get $ x(t) = rep_4(x_1(t)) $

We know that the CTFT of x1(t) is:
$ x1(f) = sinc(2(f-\frac{1}{4} ) + sinc(2(f + \frac{1}{4}) $
We also know from alabechs notes section 1.4.1 that $ rep_T(x_1(t)) \Rightarrow \frac{1}{T} comb_{1/T}(X_1(f)) $

Put all the pieces together and you get something that looks like
$ X(f) = \frac{1}{4} comb_{1/4}(sinc(2(f-\frac{1}{4} ) + sinc(2(f + \frac{1}{4})) $ --Drestes 22:53, 10 February 2009 (UTC)


  • Can you write your answer using a comb operator? --Mboutin 10:45, 9 February 2009 (UTC)
  • How did you get to that answer? Please add some intermediate steps. --Mboutin 10:50, 9 February 2009 (UTC)

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