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+ | Since each subset is disjoint from all of the others it is just the sum of the cardinalities of each subset.--[[User:Spfeifer|Spfeifer]] 14:01, 22 January 2009 (UTC) |
Revision as of 09:01, 22 January 2009
Does anyone know what to do with this problem??
Since each subset is disjoint from all of the others it is just the sum of the cardinalities of each subset.--Spfeifer 14:01, 22 January 2009 (UTC)