Difference between revisions of "Talk:6" - Rhea

Latest revision as of 10:42, 27 January 2009

I don't even know how to solve the first problem.

I tried it this way.

Base step: P(0)

0*0 = 0 (0+1)! -1 =0

It is true

Inductive step: Assume P(k) is true then P(k+1) is also true.

P(k) = 1*1! + 2+2! +…………………………..+k*k! = (k+1)! -1 P(k+1) = 1*1! + 2+2! +…………………………..+(k+1)*(k+1)! = (k+2)!-1

From the first equation

(1*1! + 2+2! +…………………………..+ k*k!) +(k+1)*(k+1)! = (k+1)+1! -1

                                                         = (k+2)! -1 

Is it correct?