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It states at the beginning of the problem that p is a prime.
 
It states at the beginning of the problem that p is a prime.
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I worked with my guess from the previous homework and applied it to the U(p^n).  I tested it with the first two primes (2 and 3).  This is what I have:
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|U(p^n)| = |U(1)|*|U(p^n)| if p is even, n>=0
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|U(p^n)| = |U(p)|*|U(p^n-1)| if p is odd, n>=0
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I'm not sure if it's right, though. -Kristie

Revision as of 15:49, 24 September 2008

The latter part of the question asks to find |U(750)|, and suggests using HW3 from Ch3. I'm reasonably sure this is supposed to suggest HW38 from Ch3, which can be found here.



Does anyone know how to do the first part describing U(p^n)? Is p prime or what is the question asking? -Neely


It states at the beginning of the problem that p is a prime.

__ I worked with my guess from the previous homework and applied it to the U(p^n). I tested it with the first two primes (2 and 3). This is what I have: |U(p^n)| = |U(1)|*|U(p^n)| if p is even, n>=0 |U(p^n)| = |U(p)|*|U(p^n-1)| if p is odd, n>=0

I'm not sure if it's right, though. -Kristie

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

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