Line 2: Line 2:
  
 
Answer:
 
Answer:
Suppose H contains at least one odd permutation, say <math>\sigma</math>. For each odd permutation <math>\beta</math>, the permutation <math>\sigma \beta</math>
+
Suppose H contains at least one odd permutation, say <math>\sigma</math>. For each odd permutation <math>\beta</math>, the permutation <math>\sigma \beta</math> is even.
 +
 
 +
Note:
 +
<math>\sigma</math>  = odd
 +
<math>\beta</math> = odd
 +
<math>\sigma \beta </math> = even

Revision as of 14:24, 9 September 2008

Question: Show that if H is a subgroup of $ S_n $, then either every member of H is an even permutation or exactly half of the members are even.

Answer: Suppose H contains at least one odd permutation, say $ \sigma $. For each odd permutation $ \beta $, the permutation $ \sigma \beta $ is even.

Note: $ \sigma $ = odd $ \beta $ = odd $ \sigma \beta $ = even

Alumni Liaison

Have a piece of advice for Purdue students? Share it through Rhea!

Alumni Liaison