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On doin a Laplace Transform | On doin a Laplace Transform | ||
| − | <math>X(s)= \int_{-\infty}^{\infty}x(t){e^{- | + | <math>X(s)= \int_{-\infty}^{\infty}x(t){e^{-st}}\, dt</math> |
Revision as of 11:12, 19 November 2008
== Fundamentals of Laplace Transform ==
Let the signal be:
$ x(t) =e^ {-at} \mathit{u} (t) $
On doin a Laplace Transform
$ X(s)= \int_{-\infty}^{\infty}x(t){e^{-st}}\, dt $
