Line 2: Line 2:
  
  
−
       <math>x(t) =e^-^a^t  \mathit{u} (t)</math>
+
       <math>x(t) =e^ {-at} \mathit{u} (t)</math>

Revision as of 10:59, 19 November 2008

                             == Fundamentals of Laplace Transform ==



     $ x(t) =e^ {-at} \mathit{u} (t) $
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