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<math> \delta (t-t_0)----> e^{jwt_0} \! </math>
+
<math> x(t)=\delta (t-t_0)\longrightarrow {\mathcal X}(\omega)= e^{jwt_0} \! </math>

Latest revision as of 11:16, 14 November 2008

$ x(t)=\delta (t-t_0)\longrightarrow {\mathcal X}(\omega)= e^{jwt_0} \! $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood