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| − | <math>\frac {1}{T} \int_{0}^{T}|x(t)|^2 dt = \sum_{k=-\infty}{infty}|a_k|^2</math> | + | <math>\frac {1}{T} \int_{0}^{T}|x(t)|^2 dt = \sum_{k=-\infty}^{\infty}|a_k|^2</math> |
Revision as of 11:55, 15 October 2008
$ \frac {1}{T} \int_{0}^{T}|x(t)|^2 dt = \sum_{k=-\infty}^{\infty}|a_k|^2 $
