(New page: <math>x(at) <----> \frac{1}{abs{a}}X(\frac{j\omega }{a}\,</math>)
 
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<math>x(at)      <---->    \frac{1}{abs{a}}X(\frac{j\omega }{a}\,</math>
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<math>x(at)      <---->    \frac{1}{abs{a}}X(\frac{j\omega }{a})\,</math>

Revision as of 09:17, 14 October 2008

$ x(at) <----> \frac{1}{abs{a}}X(\frac{j\omega }{a})\, $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood