(Part A)
(Part A)
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==Part A==
 
==Part A==
  
 +
==
 
<math>y(t) = K x(t-a)</math>
 
<math>y(t) = K x(t-a)</math>
  
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<math>y(t) = K e^{jw(t-a)}</math>
 
<math>y(t) = K e^{jw(t-a)}</math>
  
<math>= K e^{-jwa}e^{jwt}</math>
+
<math>= K e^{-jwa}e^{jwt}</math> ==

Revision as of 17:20, 26 September 2008

Part A

== $ y(t) = K x(t-a) $

if $ x(t)=e^{jwt} $ was inputed to the system

$ y(t) = K e^{jw(t-a)} $

$ = K e^{-jwa}e^{jwt} $ ==

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood