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2. <math>\sum_{k = 0}^{3}x[n] = (2 + j)</math> | 2. <math>\sum_{k = 0}^{3}x[n] = (2 + j)</math> | ||
| − | 3. for the given value of k, <math>e^{jk2\pi} = 1\,</math>, then that <math>a_{k}</math> | + | 3. for the given value of k, <math>e^{jk2\pi} = 1\,</math>, then that <math>a_{k} = \frac{1}{2}\,</math> |
Revision as of 15:16, 26 September 2008
DT Signal:
1. Signal is periodic with N = 4
2. $ \sum_{k = 0}^{3}x[n] = (2 + j) $
3. for the given value of k, $ e^{jk2\pi} = 1\, $, then that $ a_{k} = \frac{1}{2}\, $
Solution
$ a_{0} = \frac{2 + j}{4} $
