Line 18: Line 18:
  
 
<math>F(z) = \sum_{m=-\infty}^\infty \delta[m-10]e^{jmw}</math>
 
<math>F(z) = \sum_{m=-\infty}^\infty \delta[m-10]e^{jmw}</math>
 +
 +
therefore,
 +
 +
<math>F(z) = e^{10jw}</math>

Revision as of 13:06, 26 September 2008

assume that

$ y[n] = x[n-10] $

unit impulse response

$ h[n] = \delta[n] $

$ y[n] = h[n] $

then we can can a unit impulse response as

$ h[n]= \delta[n-10] $

for the frequency response,

$ F(z) = \sum_{m=-\infty}^{\infty} h[m]e^{jmw} $

$ F(z) = \sum_{m=-\infty}^\infty \delta[m-10]e^{jmw} $

therefore,

$ F(z) = e^{10jw} $

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