Line 1: Line 1:
 
<math>
 
<math>
\y(t) = int_{-N}^{N} e^x\, dx
+
y(t) =
 +
\int_{-N}^{N} e^x\, dx
 
</math>
 
</math>

Revision as of 11:47, 26 September 2008

$ y(t) = \int_{-N}^{N} e^x\, dx $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood