Line 3: Line 3:
 
1. <math>N = 2\,</math>
 
1. <math>N = 2\,</math>
  
2. <math>a_k = 0\,</math> for all non-fractional <math> k \,</math>
+
2. <math>a_k = 0\,</math> for all |k|>1
  
 
3. <math>\sum_{n=0}^{3}x[n]=2</math>
 
3. <math>\sum_{n=0}^{3}x[n]=2</math>

Revision as of 09:55, 26 September 2008

Informations

1. $ N = 2\, $

2. $ a_k = 0\, $ for all |k|>1

3. $ \sum_{n=0}^{3}x[n]=2 $

4. $ \sum_{n=0}^{3}(-1)^nx[n]=5 $

Inspections

From first information, we can directly subtitute N into:

$ x[n]=\sum_{n=0}^{3}a_ke^{jk(2\pi/2)n}\, $

$ x[n]=\sum_{n=0}^{3}a_ke^{jk\pi n}\, $

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin