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| − | <math>5cos(\frac{2\pi}{9}t)+1\!</math> | + | <math>x(t) = 5cos(\frac{2\pi}{9}t)+1\!</math> |
Revision as of 12:11, 25 September 2008
GUESS THE PERIODIC SIGNAL
1. $ x(t)\! $ is an $ odd\! $ function.
2. $ x(t)\! $ has a fundamental period of $ T = 9\! $
3. The Pk-Pk of the function is 10.
4. The function is offset by a value of +1
ANSWER
$ x(t) = 5cos(\frac{2\pi}{9}t)+1\! $
