| Line 7: | Line 7: | ||
h(t) = 10delta(t-1) | h(t) = 10delta(t-1) | ||
| − | H(s) = \int_{-\infty}^{\infty} h(t) | + | <math>H(s) = \int_{-\infty}^{\infty} h(t)</math> |
| − | H(s) = \int_{-\infty}^{\infty} 10delta(t-1) | + | <math>H(s) = \int_{-\infty}^{\infty} 10delta(t-1)</math> |
Revision as of 10:59, 25 September 2008
CT LTI system:
y(t) = 10x(t-1)
plugging in delta(t) into the system we get:
h(t) = 10delta(t-1)
$ H(s) = \int_{-\infty}^{\infty} h(t) $
$ H(s) = \int_{-\infty}^{\infty} 10delta(t-1) $
