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2. The fundamental period of the signal is 8 | 2. The fundamental period of the signal is 8 | ||
| − | 3. Hint: <math>{1 \over 2}\sin({pi \over 4}t)</math> | + | 3. Hint: <math>{1 \over 2}\sin({\pi \over 4}t)</math> |
==Solution== | ==Solution== | ||
| − | The answer is <math>{1 \over 2}\sin({pi \over 4}t)</math> Surprise! | + | The answer is <math>{1 \over 2}\sin({\pi \over 4}t)</math> Surprise! |
Revision as of 16:49, 25 September 2008
Homework 4 Ben Horst: 4.1 :: 4.3 :: 4.5
Problem
1. The signal has only two Fourier coefficients (all the rest are 0)
2. The fundamental period of the signal is 8
3. Hint: $ {1 \over 2}\sin({\pi \over 4}t) $
Solution
The answer is $ {1 \over 2}\sin({\pi \over 4}t) $ Surprise!
