(New page: As henry has mentioned this is a problem that is similar to the one discussed in class. First bar purchased = 1 coupon 1 = number of extra bars for a different coupon 1 is a geometr...)
 
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1= 1 coupon
  
 
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2 = number of extra bars for a different coupon
 
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2 is a geometric Random variable
First bar purchased = 1 coupon
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1 = number of extra bars for a different coupon
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1 is a geometric Random variable
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  = # of extra bars after 2nd coupon to get 3rd coupon
 
  = # of extra bars after 2nd coupon to get 3rd coupon
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E[# needed]=  
 
E[# needed]=  
  
Retrieved from "http://kiwi.ecn.purdue.edu/ECE302Fall2008sanghavi/index.php/5.1_-_Henry_Michl"
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Retrieved from "http://kiwi.ecn.purdue.edu/ECE302Fall2008sanghavi/index.php/5.1_-_Henry_Michl

Revision as of 17:11, 5 October 2008

As henry has mentioned this is a problem that is similar to the one discussed in class.


1= 1 coupon

2 = number of extra bars for a different coupon 2 is a geometric Random variable

= # of extra bars after 2nd coupon to get 3rd coupon

X3 is geom

X4 is geom

Xn is geom

Avg. # of coupons E[# needed]=

Retrieved from "http://kiwi.ecn.purdue.edu/ECE302Fall2008sanghavi/index.php/5.1_-_Henry_Michl

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood