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From the plot above, N = 4:
 
From the plot above, N = 4:
  
<math>a_{k} = \frac{1}{4} \sum_{n=0}^{3} x[n] e^{-jk \frac{2 \pi}{4} n}</math>
+
<math>a_{k} = \frac{1}{4} \sum_{n=0}^{3} x[n] e^{-jk \frac{\pi}{2} n}</math>

Revision as of 16:30, 23 September 2008

Periodic DT Signal

The following plot shows two periods of the periodic DT signal $ x[n] $, a sawtooth:

SawDTJP ECE301Fall2008mboutin.jpg

Fourier Series Coefficients

$ a_{k} = \frac{1}{N} \sum_{n=0}^{N-1} x[n] e^{-jk \frac{2 \pi}{N} n} $

From the plot above, N = 4:

$ a_{k} = \frac{1}{4} \sum_{n=0}^{3} x[n] e^{-jk \frac{\pi}{2} n} $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood