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= <math>\frac{e^{jt}-e^{-jt}}{2i}</math>+<math>2*\frac{e^{2jt}+{e^{-2jt}}}{2}</math> | = <math>\frac{e^{jt}-e^{-jt}}{2i}</math>+<math>2*\frac{e^{2jt}+{e^{-2jt}}}{2}</math> | ||
− | = <math>\frac{-j{e^{jt}}}{2}</math> | + | = <math>\frac{-j{e^{jt}}}{2}+\frac{j{e^{-jt}}}{2}+{e^{2jt}}+{e^{-2jt}}</math> |
Revision as of 13:54, 23 September 2008
CT SIGNAL & ITS FOURIER COEFFICIENTS
Let the input signal be
$ x(t)=sint +2cos2t $
= $ \frac{e^{jt}-e^{-jt}}{2i} $+$ 2*\frac{e^{2jt}+{e^{-2jt}}}{2} $
= $ \frac{-j{e^{jt}}}{2}+\frac{j{e^{-jt}}}{2}+{e^{2jt}}+{e^{-2jt}} $