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<math>x(t) = 4\sin(5 \pi t) - (2 + j)\cos(3 \pi t)\,</math>
 
<math>x(t) = 4\sin(5 \pi t) - (2 + j)\cos(3 \pi t)\,</math>
  
<math>x(t) = 4 * \frac{e^{j5\pit} - e^{-j5\pit}}{2} - (2+j)*\frac{e^{j3\pit} + e^{-j3\pit}}{2}\,</math>
+
<math>x(t) = 4 * \frac{e^{j5\pi t} - e^{-j5\pi t}}{2} - (2+j)*\frac{e^{j3\pi t} + e^{-j3\pi t}}{2}\,</math>

Revision as of 17:21, 22 September 2008

CT signal:

$ x(t) = 4\sin(5 \pi t) - (2 + j)\cos(3 \pi t)\, $

$ x(t) = 4 * \frac{e^{j5\pi t} - e^{-j5\pi t}}{2} - (2+j)*\frac{e^{j3\pi t} + e^{-j3\pi t}}{2}\, $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang