(New page: Bob can decrypt the message by multiplying 3 letter sequences by the inverse of the encryption matrix.)
 
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Bob can decrypt the message by multiplying 3 letter sequences by the inverse of the encryption matrix.
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Bob can decrypt the message by multiplying 3 letter sequences by the inverse of the encryption matrix. <br>
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Because this encryption is linear, Eve doesn't need to know the inverse to decrypt messages.  She can write any unknown message as linear multiples of the message she knows. <br>
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<2,23,3> can be written as 1<2,0,0> + 23<0,1,0> + 1<0,0,3> <br>
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Since we know the inputs that yield the vectors <2,0,0> , <0,1,0> , and <0,0,3>, linearity says the corresponding input is:<br>
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:1<1,0,4> + 23<0,1,0> + 1<1,0,1> <br>
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which simplifies to <2,23,5>, or BWE

Revision as of 07:20, 19 September 2008

Bob can decrypt the message by multiplying 3 letter sequences by the inverse of the encryption matrix.

Because this encryption is linear, Eve doesn't need to know the inverse to decrypt messages. She can write any unknown message as linear multiples of the message she knows.


<2,23,3> can be written as 1<2,0,0> + 23<0,1,0> + 1<0,0,3>
Since we know the inputs that yield the vectors <2,0,0> , <0,1,0> , and <0,0,3>, linearity says the corresponding input is:

1<1,0,4> + 23<0,1,0> + 1<1,0,1>

which simplifies to <2,23,5>, or BWE

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett