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<math>\cos 2t = \mathrm{Re}\{e^{jt}\} ={e^{2jt} + e^{-2jt} \over 2}</math> | <math>\cos 2t = \mathrm{Re}\{e^{jt}\} ={e^{2jt} + e^{-2jt} \over 2}</math> | ||
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| + | <math>\cos 2t = e^{2jt}/2 + e^{-2jt}/2 </math> | ||
Revision as of 05:15, 19 September 2008
The basics of linearity
$ e^{(2jt)} $ --->[system]--->$ te^{(-2jt)} $
$ e^{(-2jt)} $ --->[system]--->$ te^{(2jt)} $
$ \cos x = \mathrm{Re}\{e^{ix}\} ={e^{ix} + e^{-ix} \over 2} $
$ \cos 2t = \mathrm{Re}\{e^{jt}\} ={e^{2jt} + e^{-2jt} \over 2} $
$ \cos 2t = e^{2jt}/2 + e^{-2jt}/2 $
