(Time Invariant System)
(Stable System)
 
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==Stable System==  
 
==Stable System==  
1-        Give a formal definition of a “memoryless system”. Give a formal definition of a “system with memory”.
 
  
2-        Give a formal definition of a “causal system”. Give a formal definition of a non-causal system.
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A system is stable if bounded inputs yield bounded outputs.
  
3-        Give a formal definition of a “linear system”. Give a formal definition of a “non-linear system”.
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A system is not stable if bounded inputs yield unbounded outputs.
 
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4-        Give a formal definition of a “time invariant system”. Give a formal definition of a “time variant system”.
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5-        Give a formal definition of a “stable system”. Give a formal definition of an unstable system.
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Latest revision as of 16:50, 17 September 2008

Memoryless System

A memoryless system is a system for which for any real number $ t_0 $, the output at $ t_0 $ depends only on that value of t.

A system with memory is a system whose output depends on the value $ t_0 $ as well as another value of t for any given $ t_0 $

Causal System

A system is causal if the output at any given time only depends on the input in present and past (not the future)

A system is not causal if the output at any given time depends on input in the future.

Linear System

A system is linear if for any complex constants a and b and for any inputs $ x_1(t) $ and $ x_2(t) $ yielding output $ y_1(t) $ and $ y_2(t) $ respectively, the response is $ a*x_1(t)+b*x_2(t) ==> [SYSTEM] ==> a*y_1(t) + b*y_2(t) $

A system is nonlinear if for any complex constants a and b and for any inputs $ x_1(t) $ and $ x_2(t) $ yielding output $ y_1(t) $ and $ y_2(t) $ respectively, the response is $ a*x_1(t)+b*x_2(t) ==> [SYSTEM] ==> z(t) $ where $ z(t) $ is NOT the constants a and b multiplied by the outputs $ y_1(t) $ and $ y_2(t) $

Time Invariant System

A system is called time invariant if for any input signal x(t) yielding output y(t) and for any time $ t_0 $ the output to the shifted input $ x(t-t_0) $ is the shifted output $ y(t-t_0) $.

A system is not time invariant if shifting the input does not yield the same output shifted by the same amount.

Stable System

A system is stable if bounded inputs yield bounded outputs.

A system is not stable if bounded inputs yield unbounded outputs.

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang