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<br>
 
<br>
 
They will change into:
 
They will change into:
 +
<math>e^{(2jt)} = cos{(2t)} + jsin{(2t)} --> system --> t*{(cos{(2t)} - jsin{(2t)})}\,</math><br>
 +
<math>e^{(-2jt)} = cos{(2t)} - jsin{(2t)} --> system --> t*{(cos{(2t)} + jsin{(2t)})}\,</math><br><br>

Revision as of 09:28, 16 September 2008

Since $ e^{2jt} \rightarrow system \rightarrow te^{-2jt}\! $
$ e^{-2jt} \rightarrow system \rightarrow te^{2jt}\! $

and using euler formula, we can replace exponent expressions with

Euler's formula: $ e^{iy}=cos(y)+isin(y)\, $


They will change into: $ e^{(2jt)} = cos{(2t)} + jsin{(2t)} --> system --> t*{(cos{(2t)} - jsin{(2t)})}\, $
$ e^{(-2jt)} = cos{(2t)} - jsin{(2t)} --> system --> t*{(cos{(2t)} + jsin{(2t)})}\, $

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Questions/answers with a recent ECE grad

Ryne Rayburn