(New page: == Comments == Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal ...) |
(→Comments) |
||
Line 1: | Line 1: | ||
== Comments == | == Comments == | ||
− | Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right | + | Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right. |
+ | |||
+ | Comment by : 00185-37978 |
Revision as of 17:30, 15 September 2008
Comments
Instead of this method, we should expand it in terms of $ \cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\, $, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right.
Comment by : 00185-37978