(New page: The original code below uses Ts of 0.07, or a '''sampling rate''' of 0.7 seconds. Therefore, the plot appears to only show one cycle of the sinusoid. <pre>F0 =13; T0 =1/F0; Ts = 0.07; t ...) |
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− | The original code below uses Ts of 0.07, or a '''sampling rate''' of 0. | + | The original code below uses Ts of 0.07, or a '''sampling rate''' of 0.07 seconds. Therefore, the plot appears to only show one cycle of the sinusoid. |
<pre>F0 =13; | <pre>F0 =13; |
Latest revision as of 14:05, 12 September 2008
The original code below uses Ts of 0.07, or a sampling rate of 0.07 seconds. Therefore, the plot appears to only show one cycle of the sinusoid.
F0 =13; T0 =1/F0; Ts = 0.07; t = 0:Ts:13*T0; x = real(exp(j*(2*pi*F0*t-pi/2))); plot(t,x);
If the sampling rate is changed to 0.001, it will be enough to see all 13 cycles of the sinusoid. Increasing the sampling rate will give a much smoother representation of the sinusoid.
F0 =13; T0 =1/F0; Ts = 0.001; t = 0:Ts:13*T0; x = real(exp(j*(2*pi*F0*t-pi/2))); plot(t,x);